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6n^2-72n+162=0
a = 6; b = -72; c = +162;
Δ = b2-4ac
Δ = -722-4·6·162
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-36}{2*6}=\frac{36}{12} =3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+36}{2*6}=\frac{108}{12} =9 $
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